Powie mi ktos jakim cudem po kliknieciu submit isset($_POST['submit']) nie spelnia warunku w ifie ?
wszystko dzieje sie w tym samym pliku a oto kod:
<?php
$mysqli = new mysqli('localhost','XXXX', "XXXX", "XXXX");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
if (!$mysqli->set_charset("utf8")) {
printf("Error loading character set utf8: %s\n", $mysqli->error);
}
if(isset($_POST['submit']))
{
$data=date("D M j G:i:s T Y");
//formularz jest wyslany
if ($stmt = $mysqli->prepare("INSERT INTO `timeseer`.`bug_report` (`id_buga` ,`tresc` ,`status` ,`data`)VALUES (NULL , ?, 'w trakcie realizacji',?);")) {
/* bind parameters for markers */
$stmt->bind_param("s",$_POST['blad']);
$stmt->bind_param("s",$data);
/* execute query */
$stmt->execute();
}
$stmt->close();
/* bind result variables */
header('Location: errorlog.php');
}
else echo "dupa";
?>
<hr>
<center>
<font size=10 > ` Strona do zglaszanie buentow ` </span> <br><br><br>
<form action="errorlog.php" method="POST">
buont: <input type="text" name="blad" style="width:700px;"><input type = "submit" name = "submit" value = "Submit"/>
</form>
</span>
<hr>
<?php
if ($stmt = $mysqli->prepare("SELECT * FROM `timeseer`.`bug_report`;")) {
$stmt->execute();
$result=$stmt->get_result();
while($row = $result->fetch_array(MYSQLI_NUM))
{
echo $row[0]." | ".$row[1]." | ".$row[2]." | ".$row[3]."<br>";
}
}
$stmt->close();
?>
<hr>
z gory dziekuje!