Czesc wszystkim,

wlasnie probuje ogarnac temat spring security. Znalazlem jakies przyklady na stronie mkyong.com i mam maly problem. Tzn. jest tam przyklad, w ktorym dane do logowania sa w pliku .xml - ten udalo mi sie uruchomic. Natomiast kiedy uruchamiam ten sam przyklad, tyle ze user i haslo z bazy danych dostaje http404. Mozecie mi pomoc?

Oto kod:


package com.kamil.common1.controller;

import java.security.Principal;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
 
@Controller
public class LoginController {
 
    @RequestMapping(value="/welcome", method = RequestMethod.GET)
    public String printWelcome(ModelMap model, Principal principal ) {
 
        String name = principal.getName();
        model.addAttribute("username", name);
        model.addAttribute("message", "Spring Security Custom Form example");
        return "hello";
 
    }
 
    @RequestMapping(value="/login", method = RequestMethod.GET)
    public String login(ModelMap model) {
 
        return "login";
 
    }
 
    @RequestMapping(value="/loginfailed", method = RequestMethod.GET)
    public String loginerror(ModelMap model) {
 
        model.addAttribute("error", "true");
        return "login";
 
    }
 
    @RequestMapping(value="/logout", method = RequestMethod.GET)
    public String logout(ModelMap model) {
 
        return "login";
 
    }
 
}

mvc-dispatcher-servlet.xml

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <context:component-scan base-package="com.kamil.common1.controller" />

    <bean
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix">
            <value>/WEB-INF/pages/</value>
        </property>
        <property name="suffix">
            <value>.jsp</value>
        </property>
    </bean>

    <bean id="messageSource"
        class="org.springframework.context.support.ResourceBundleMessageSource">
        <property name="basenames">
            <list>
                <value>mymessages</value>
            </list>
        </property>
    </bean>

    <bean id="dataSource"
        class="org.springframework.jdbc.datasource.DriverManagerDataSource">

        <property name="driverClassName" value="org.postgresql.Driver" />
        <property name="url" value="jdbc:postgresql://localhost:5432/springtut" />
        <property name="username" value="postgres" />
        <property name="password" value="qwe" />
    </bean>

</beans>

Spring-security.xml


<beans:beans xmlns="http://www.springframework.org/schema/security"
    xmlns:beans="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/security
    http://www.springframework.org/schema/security/spring-security-3.0.3.xsd">
 
    <http auto-config="true">
        <intercept-url pattern="/welcome*" access="ROLE_USER" />
        <form-login login-page="/login" default-target-url="/welcome"
            authentication-failure-url="/loginfailed" />
        <logout logout-success-url="/logout" />
    </http>
 
    <authentication-manager>
       <authentication-provider>
        <jdbc-user-service data-source-ref="dataSource"
 
           users-by-username-query="
              select username,password, enabled 
              from users where username=?" 
 
           authorities-by-username-query="
              select u.username, ur.authority from users u, user_roles ur 
              where u.user_id = ur.user_id and u.username =?  " 
 
        />
       </authentication-provider>
    </authentication-manager>
 
</beans:beans>

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:web="http://xmlns.jcp.org/xml/ns/javaee"
    xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
    id="WebApp_ID" version="2.4">
    <display-name>Spring DB Application</display-name>
    
    <!-- Spring MVC -->
    <servlet>
        <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            /WEB-INF/mvc-dispatcher-servlet.xml,
            /WEB-INF/spring-database.xml,
            /WEB-INF/spring-security.xml
        </param-value>
    </context-param>
    
    <!-- Spring Security -->
    <filter>
        <filter-name>springSecurityFilterChain</filter-name>
        <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>
    <filter-mapping>
        <filter-name>springSecurityFilterChain</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>
</web-app>

Procz tego sa jeszcze 2 stronki jsp, ale te wygladaje dokladnie tak samo, jak w przypadku xml, wiec sadze, ze akurat tam jest wszystko ok...