Witam, chciałem zrobić Ranking TOP 15 sortowany na podstawie "zabójstw".
Błędy:```php
rning: mysql_query() expects parameter 1 to be string, object given in /home/u669081928/public_html/ranking.php on line 90
Warning: mysql_fetch_array() expects parameter 1 to be resource, null given in /home/u669081928/public_html/ranki
Skrypt: ```php
<?php
$con=mysqli_connect("xxx.xxx.xxx.xxx","xxx","xxx","xxx");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysql_query($con, "SELECT kills FROM dx_users ORDER BY kills DESC LIMIT 10");
while($row=mysql_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['kills'] . "</td>";
echo "<td>" . $row['deaths'] . "</td>";
echo "</tr>";
}
?>